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.5x+.5x^2=3
We move all terms to the left:
.5x+.5x^2-(3)=0
a = .5; b = .5; c = -3;
Δ = b2-4ac
Δ = .52-4·.5·(-3)
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.5)-\sqrt{6.25}}{2*.5}=\frac{-0.5-\sqrt{6.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.5)+\sqrt{6.25}}{2*.5}=\frac{-0.5+\sqrt{6.25}}{1} $
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